y' = (x + 1)e^x
Para x = 0
y' = 1
Pendiente normal
m = -1/y' =-1
Recta normal
y - 0 = (-1) (x - 0)
y = -x
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Verified answer
y' = (x + 1)e^x
Para x = 0
y' = 1
Pendiente normal
m = -1/y' =-1
Recta normal
y - 0 = (-1) (x - 0)
y = -x
*********