the way it is written, only the √3 is in the denominator. It is unclear if you want 5/√3 - 1 or 5/(√3 -1).
If it's the first case, multiply numerator and denominator by √3 to get 5√3 / 3 - 1 = (5√3 - 3)/3
if it's the second case, multiply numerator and denominator by the conjugate of the denominator:
5 / (√3 - 1)
= 5(√3 + 1) / (√3 - 1)(√3 + 1)
= 5(√3 + 1) / (3 - 1)
= 5(√3 + 1) / 2
that's it! ;)
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Verified answer
the way it is written, only the √3 is in the denominator. It is unclear if you want 5/√3 - 1 or 5/(√3 -1).
If it's the first case, multiply numerator and denominator by √3 to get 5√3 / 3 - 1 = (5√3 - 3)/3
if it's the second case, multiply numerator and denominator by the conjugate of the denominator:
5 / (√3 - 1)
= 5(√3 + 1) / (√3 - 1)(√3 + 1)
= 5(√3 + 1) / (3 - 1)
= 5(√3 + 1) / 2
that's it! ;)