4-x= √(x+2)
(4-x)² = x + 2
x² - 8x +16 = x + 2
x² - 9x + 14 = 0
x = [-b ± √(b² - 4ac)]/2a
x = [-(-9) ± √((-9)² - 4(1)14)]/2(1)
x = [9 ± √(81 - 56)]/2
x = [9 ± √25]/2
x = [9 ± 5]/2
x' = [9+5]/2
x' = 14/2
x' = 7
x'' = [9-5]/2
x'' = 4/2
x'' = 2
4 - 7 = √(7+2)
4 - 7 = √9
-3 = 3 Falso
4-2= √(2+2)
4-2 = √4
2 = 2 Verdadeiro
S = {2}
4-x= raiz de x+2
(4-x)² = x+2
16 - 8x + x² = x + 2
x² -9x + 14 = 0
x" = 2
QSL?
e igual a 2/3
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Verified answer
4-x= √(x+2)
(4-x)² = x + 2
x² - 8x +16 = x + 2
x² - 9x + 14 = 0
x = [-b ± √(b² - 4ac)]/2a
x = [-(-9) ± √((-9)² - 4(1)14)]/2(1)
x = [9 ± √(81 - 56)]/2
x = [9 ± √25]/2
x = [9 ± 5]/2
x' = [9+5]/2
x' = 14/2
x' = 7
x'' = [9-5]/2
x'' = 4/2
x'' = 2
4-x= √(x+2)
4 - 7 = √(7+2)
4 - 7 = √9
-3 = 3 Falso
4-2= √(2+2)
4-2 = √4
2 = 2 Verdadeiro
S = {2}
4-x= raiz de x+2
(4-x)² = x+2
16 - 8x + x² = x + 2
x² -9x + 14 = 0
x' = 7
x" = 2
QSL?
e igual a 2/3