It is actually a DEFINITION, coming from the definition of the unit circle.
sin(a-b)=sinacosb-cosasinb
sin(pi-x)=sinpicosx-cospisinx
sinpi=0 and cospi=1
sin(pi-x)=0cosx-1(sinx)
sin(pi-x)=sinx.
SIN(A-B)=SINACOSB-COSASINB
SIN(pi-X)=SINpiCOSX-COSpiSINX
SIN(pi-X)=0COSX-(-1)SINX
SIN(pi-X)=+SINX
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Verified answer
It is actually a DEFINITION, coming from the definition of the unit circle.
sin(a-b)=sinacosb-cosasinb
sin(pi-x)=sinpicosx-cospisinx
sinpi=0 and cospi=1
sin(pi-x)=0cosx-1(sinx)
sin(pi-x)=sinx.
SIN(A-B)=SINACOSB-COSASINB
SIN(pi-X)=SINpiCOSX-COSpiSINX
SIN(pi-X)=0COSX-(-1)SINX
SIN(pi-X)=+SINX