cos(π/2+θ)=-sinθ
cos(π/2+θ)= cos(π/2)*cosθ -sin(π/2)*sinθ =
cos(π/2) =0
sin(π/2)=1
cos(π/2)*cosθ -sin(π/2)*sinθ = 0*cosθ -1*sinθ =-sinθ
cos(pi/2 + theta) = cos(pi/2)*costheta - sin(pi/2)* sin theta
= 0 -1*sin theta = -sin theta
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Verified answer
cos(π/2+θ)= cos(π/2)*cosθ -sin(π/2)*sinθ =
cos(π/2) =0
sin(π/2)=1
cos(π/2)*cosθ -sin(π/2)*sinθ = 0*cosθ -1*sinθ =-sinθ
cos(pi/2 + theta) = cos(pi/2)*costheta - sin(pi/2)* sin theta
= 0 -1*sin theta = -sin theta