Prove that ∑r² (n = 1 to n = n) = (1/6)n(n+1)(2n+1)?
or 1² + 2² + 3² + 4² + 5² + 6² + .... + n² = (1/6)n(n+1)(2n+1)
when you know that 1 + 2 + 3 + 4 + 5 + .... + n = n(n + 1)/2
Update:sorry for little mistake.
∑r² (r = 1 to r = n) = (1/6)n(n+1)(2n+1)?
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Proof by induction
I think I'm to old for this