Prove that µ(n)µ(n+2)µ(n+3)=0?
Prove µ(n)µ(n+2)µ(n+3)=0
where µ(n) = (1 if n=1) (0 if p^2 divide n) ( (-1)^r if n = p1...pr)
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Prove µ(n)µ(n+2)µ(n+3)=0
where µ(n) = (1 if n=1) (0 if p^2 divide n) ( (-1)^r if n = p1...pr)
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What about n=3?
µ(3)µ(5)µ(6) = (-1)(-1)(1) = 1
....as I read that definition.
Also, it looks like µ(35)µ(37)µ(38) = (1)(-1)(1) = -1