A) o 8º termo de.
b) o número de termos dessa sequência.
a_
a8=2+7(1/3)
a8=2+7/3
a8=13/3
18=2+(n-1)1/3
18=2-n/3-1/3
18-5/3=n/3
49/3=n/3
n=49
a1 = 2 = 6/3
a2 = 7/3
r = a2 - a1 = 7/3 - 6/3 = 1/3
a8 = a1 + 7r = 6/3 + 7/3 = 13/3
an = 18 = 54/3
an = a1 + (n - 1)*r
(n - 1)*r = an - a1
n - 1 = (an - a1)/r
n = (an - a1)/r + 1
n = (54/3 - 6/3)/(1/3) + 1
n = 54 - 6 + 1 = 49 termos
pronto
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Verified answer
a_
a8=2+7(1/3)
a8=2+7/3
a8=13/3
18=2+(n-1)1/3
18=2-n/3-1/3
18-5/3=n/3
49/3=n/3
n=49
a1 = 2 = 6/3
a2 = 7/3
r = a2 - a1 = 7/3 - 6/3 = 1/3
a8 = a1 + 7r = 6/3 + 7/3 = 13/3
an = 18 = 54/3
an = a1 + (n - 1)*r
(n - 1)*r = an - a1
n - 1 = (an - a1)/r
n = (an - a1)/r + 1
n = (54/3 - 6/3)/(1/3) + 1
n = 54 - 6 + 1 = 49 termos
pronto