question on the test review my professor gave out for our test on Friday. Thank you.
Zeros = −9, 3+4i, 3−4i
f(x) = a (x+9) (x−3−4i) (x−3+4i)
f(x) = a (x+9) (x²−6x+25)
f(6) = −6
a(6+9) (36−36+25) = −6
375a = −6
a = −2/125
f(x) = −2/125 (x+9) (x²−6x+25)
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Verified answer
Zeros = −9, 3+4i, 3−4i
f(x) = a (x+9) (x−3−4i) (x−3+4i)
f(x) = a (x+9) (x²−6x+25)
f(6) = −6
a(6+9) (36−36+25) = −6
375a = −6
a = −2/125
f(x) = −2/125 (x+9) (x²−6x+25)