Verified answer

2(x-1)+(x-3)(x-2)=2(x-2)(x-2)

2x-2+x²-5x+6=2(x²-4x+4)

x²-3x+4=2x²-8x+8

x²-5x+4=0

∆=(-5)²-4(1)(4)=

25-16=9

x=(5±√9)/2

x=(5±3)/2

x'=2/2=1

x"=8/2=4

a<b

a=1

b=4

2a+3b=

2*1+3*4=

2+12=14

x - 1/x - 2 + x - 3/2 = x - 2

MMC = 2 . (x - 2)

2 . (x - 1) + (x - 2) . (x - 3) = x - 2

2x - 2 + (x² - 3x - 2x + 6) = x - 2

2x - 2 + x² - 5x + 6 = x - 2

x² + 2x - 5x - x - 2 + 9 + 2 = 0

x² - 4x + 9 = 0

∆ = (- 4)² - 4 . 1 . 9

∆ = 16 - 36 = - 20

Não existe raiz real.