Physics Problem !A 4 kg ball strikes a massive wall at 12 m/s at an angle of θ=65.0° with?
A 4 kg ball strikes a massive wall at 12 m/s at an angle of θ=65.0° with the plane of the wall. It bounces off the wall with the same speed and angle. If the ball is in contact with the wall for 0.200 s
B) what is the average force exerted by the wall on the ball in x direction
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Verified answer
RE EDIT:
There will be no change in velocity...
but the horizontal components will vary..
u = 12sin(65) (initial horizontal velocity)
v = - 12sin(65) (Final horizontal velocity)
P=mv
Change in momentum = Pfinal - Pinitial
Px = mv - mu
=(4)(-12sin(65) - 12sin(65)) = --87.0055N-s
Made a mistake in calculation :o
I = Force x Time = Change in Momentum
F = Change in Momentum/ Time = --87.0055 /0.200 = -435.0275 N
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