Physics: A uniform electric field of magnitude 8.8×105 N/C points in the positive x direction.?
a.) Find the change in electric potential energy of a 5.5-μC
charge as it moves from the origin to the point (0, 6.0 m).
ΔU =___ J
b.)Find the change in electric potential energy of a 5.5-μC
charge as it moves from the origin to the point (6.0 m, 0).
ΔU =_____ J
c.)Find the change in electric potential energy of a 5.5-μC
charge as it moves from the origin to the point (6.0 m, 6.0 m).
ΔU = _____ J
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Verified answer
a) the charge is moving perpendicularly to the field, so there is NO change in electric potential energy.
b) parellel to the field,
ΔV = -E*d = -8.8e5N/C * 6.0m = -5.28e6 V
and so
ΔU = q*ΔV = 5.5e-6C * -5.28e6V = -29 J
c) U is a scalar, so it's simply ΔU = -29 J
Hope this helps!