Phosphorous and chlorine gases combine to produce phosphorous trichloride: P2(g) + 3Cl2(g) → 2PCl3(g) ΔG° at 2?
Phosphorous and chlorine gases combine to produce phosphorous trichloride:
P2(g) + 3Cl2(g) → 2PCl3(g)
ΔG° at 298 K for this reaction is -642.9 kJ/mol. The value of ΔG at 298 K for a reaction mixture that consists of 1.7 atm P2, 1.6 atm Cl2 and 0.65 atm PCL3 is ________.
A.) -649.8
B.) -39.0
C.) -711.4
D.) -7.59 × 103
E.) -4.19 × 103
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Answers & Comments
The equation we need to use is:
∆G = ∆Go + RT ln K where K = [products]/[reactants]
= -642.9 kJ + (0.008314)(298) ln [(.65)^2 / (1.7)(1.6^3)] *notice R is in kJ now to agree with ∆Go
= -649.8 kJ
= A
If the reaction was at equilibrium (it would say it was), then the equation simplifies to:
∆Go = - RT lnK