f(x) = kx - 2
f(1) = k - 2
f(f(1)) = f(k-2) = k*(k - 2) - 2 = -3
k² - 2k + 1 = 0
(k - 1)² = 0
k = 1
f(x) = x - 2
f(1) = 1 - 2 = -1
f(f(1)) = f(-1) = -1 -2 = -3
pronto
f(f(1)) = k.f(1) - 2
f(f(1)) = k(k - 2) - 2
f(f(1)) = k² - 2k - 2
f(f(1)) = -3
k² - 2k - 2 = -3
k - 1 = 0
2
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Verified answer
f(x) = kx - 2
f(1) = k - 2
f(f(1)) = f(k-2) = k*(k - 2) - 2 = -3
k² - 2k + 1 = 0
(k - 1)² = 0
k = 1
f(x) = x - 2
f(1) = 1 - 2 = -1
f(f(1)) = f(-1) = -1 -2 = -3
pronto
f(x) = kx - 2
f(1) = k - 2
f(f(1)) = k.f(1) - 2
f(f(1)) = k(k - 2) - 2
f(f(1)) = k² - 2k - 2
f(f(1)) = -3
k² - 2k - 2 = -3
k² - 2k + 1 = 0
(k - 1)² = 0
k - 1 = 0
k = 1
2