so, I'm stumped. Can anyone help with this? Do I start by squaring both sides of the equation?
x+4√x=45
4√x=45-x
16x=x2-90x+2025
0=x2-106x+2025
0=(x-25) (x-81)
x=25, discard x=81
x+4âx=45
ok take the x on the RHS of the equation
you get
4âx = 45 -x
square both sides
16x = 2025 +x^2 -90x
x^2 - 106x + 2025 = 0
(x-25)(x-81) = 0
If you put 81 in the orignal equation , the solution cannot be obtained hence 25 is your answer
x + 4âx = 45 (subtract x from both sides)
4âx = 45 - x (square both sides)
16x = x^2 - 90x + 2025 (subtract 16x from both sides)
0 = x^2 - 106x + 2025 (factor)
0 = (x - 81)(x - 25)
x - 81 = 0 or x - 25 = 0
x = 81 or x = 25
Check:
x + 4âx = 45
81 + 4â81 = 45
81 + 4(9) = 45
117 = 45 (false, so 81 is not a solution)
25 + 4â25 = 45
25 + 4(5) = 45
45 = 45 (true)
ANSWER: x = 25
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
x+4√x=45
4√x=45-x
16x=x2-90x+2025
0=x2-106x+2025
0=(x-25) (x-81)
x=25, discard x=81
x+4âx=45
ok take the x on the RHS of the equation
you get
4âx = 45 -x
square both sides
you get
16x = 2025 +x^2 -90x
x^2 - 106x + 2025 = 0
(x-25)(x-81) = 0
If you put 81 in the orignal equation , the solution cannot be obtained hence 25 is your answer
x + 4âx = 45 (subtract x from both sides)
4âx = 45 - x (square both sides)
16x = x^2 - 90x + 2025 (subtract 16x from both sides)
0 = x^2 - 106x + 2025 (factor)
0 = (x - 81)(x - 25)
x - 81 = 0 or x - 25 = 0
x = 81 or x = 25
Check:
x + 4âx = 45
81 + 4â81 = 45
81 + 4(9) = 45
117 = 45 (false, so 81 is not a solution)
x + 4âx = 45
25 + 4â25 = 45
25 + 4(5) = 45
45 = 45 (true)
ANSWER: x = 25