Need help verifying cos(x-(3╥/2)) = -sinx?
Can anyone help my verify cos(x-(3╥/2)) = -sinx? Thanks in advance for the help!
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Can anyone help my verify cos(x-(3╥/2)) = -sinx? Thanks in advance for the help!
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Verified answer
Use compound trig formula...
cos(x - y) = cos(x)cos(y) + sin(x)sin(y)
So...
cos(x - 3π/2) = cos(x)cos(3π/2) + sin(x)sin(3π/2)
= cos(x)(0) + sin(x)(-1)
= -sin(x)
I hope this helps!