log (x²-x) = 1
. .¹²
12¹ = (x²-x)
(x²-x)-12=0
ta certo? e agora o que eu faço?
acho que: x²-x-12=0
a=1
b=-1
c=-12
bhaskara
esta certo
x² - x - 12 = 0
delta
d² = 1 + 48 = 49
d = 7
x1 = (1 + 7)/2 = 4
x2 = (1 - 7)/2 = -3
pronto
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Verified answer
esta certo
x² - x - 12 = 0
delta
d² = 1 + 48 = 49
d = 7
x1 = (1 + 7)/2 = 4
x2 = (1 - 7)/2 = -3
pronto