Measuring wavelengths with a CD, A LASER beam of wavelength λ = 632.8nm shines at normal incidence on the reflective side of a compact disc. The track of tiny pits in which information is coded onto the CD are 1.60μm apart. For what angles of reflection (measured fro m normal) will the intensity of light be maximum?
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d . sin ( angle ) = n ( wavelength)
sin (angle) = n . 0.6328 . 10^-6 / 1.6 . 10^-6
sin ( angle ) = 0.6328 / 1.6 (when n = 1 )
Sin angle = 1.2656 / 1.6 (when n = 2 )
There will be no third order angle ( the angle would have to be greater than 90 degrees )
There will be four angles of reflection. Two on each side of the central ( normal ) beam.