calculem pra mim em etapas essas expressões:
a) ab + a + b + 1
b) (2x + y)² - (x-2y)²
ab + a = a*(b + 1)
a*(b + 1) + (b + 1) = (b + 1)*(a + 1)
(2x + y)² - (x - 2y)² = (2x + y + x - 2y)*(2x + y - x + 2y) = (3x - y)*(x + 3y)
pronto
não.
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Verified answer
ab + a = a*(b + 1)
a*(b + 1) + (b + 1) = (b + 1)*(a + 1)
(2x + y)² - (x - 2y)² = (2x + y + x - 2y)*(2x + y - x + 2y) = (3x - y)*(x + 3y)
pronto
não.