Sejam as funçoes f(x) = x² -2 e g(x) = 2x+1. Determine:
a) (f ° g) (x)
b) (g ° f) (x)
f(x) = x² - 2
g(x) = 2x + 1
f(g(x)) = f(2x+1) = (2x+1)² - 2 = 4x² + 4x + 1 - 2 = 4x² + 4x - 1
g(f(x)) = g(x² - 2) = 2*(x² - 2) + 1 = 2x² - 4 + 1 = 2x² - 3
pronto
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Verified answer
f(x) = x² - 2
g(x) = 2x + 1
f(g(x)) = f(2x+1) = (2x+1)² - 2 = 4x² + 4x + 1 - 2 = 4x² + 4x - 1
g(f(x)) = g(x² - 2) = 2*(x² - 2) + 1 = 2x² - 4 + 1 = 2x² - 3
pronto