Verified answer

A)

log3(7x - 1) = 3

log(7x - 1)/log(3) = 3

log(7x - 1) = 3*log(3) = log(27)

7x - 1 = 27

7x = 28

x = 4

B)

log2(y^3 + 3) = 7

log(y^3 + 3) = 7*log(2) = log(2^7) = log(128)

y^3 + 3 = 128

y^3 = 125

y = 5

pronto

log3(base)(7x – 1) = 3

3³ = 7x – 1

7x = 27 + 1

x = 28/7

x = 4

log2(base)(y3 + 3) = 7

2^7 = y³ + 3

y³ = 128 - 3

.........___

y = ³√125

y = 5

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