the "2 means sqared.....like 4"2....4x4 ..... ok thank yoouu please do step by step thanks
G = 4π√(x² + t²)
√(x² + t²) = G/4π
x² + t² = (G/4π)²
x² = (G/4π)² - t²
x = ± √([G/4π]² - t²)
Answer: x = ± √([G/4π]² - t²)
The what is "x" in the begining?
x = sqrt ( (G/4pi)^2 - (t)^2 )
yep[
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Verified answer
G = 4π√(x² + t²)
√(x² + t²) = G/4π
x² + t² = (G/4π)²
x² = (G/4π)² - t²
x = ± √([G/4π]² - t²)
Answer: x = ± √([G/4π]² - t²)
The what is "x" in the begining?
x = sqrt ( (G/4pi)^2 - (t)^2 )
yep[