siamese_scythe thanks for your answer ^_^ my IB book was wrong then. :P
clarity is all important in mathematics....will assume you have log { base 3} √3 , which equals [1/2] = 2^(-1)
The log base 3 of sqrt(3) is 1/2, not -2. You can get there by doing
log_3 sqrt(3) = log_3 3^(1/2) = (1/2) log_3 3 = 1/2
If this is not what you meant, please write more clearly.
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clarity is all important in mathematics....will assume you have log { base 3} √3 , which equals [1/2] = 2^(-1)
The log base 3 of sqrt(3) is 1/2, not -2. You can get there by doing
log_3 sqrt(3) = log_3 3^(1/2) = (1/2) log_3 3 = 1/2
If this is not what you meant, please write more clearly.