|z| = sqrt(cos²a + sin²a) = 1.
Therefore |z^100| = 1.
Easy. It's Cos(100a) + i Sin(100a). There you go. Check de Moivre's formula.
Addendum: Ah, benoit, maybe you should reconsider?
google for de Moivre's formula
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Verified answer
|z| = sqrt(cos²a + sin²a) = 1.
Therefore |z^100| = 1.
Easy. It's Cos(100a) + i Sin(100a). There you go. Check de Moivre's formula.
Addendum: Ah, benoit, maybe you should reconsider?
google for de Moivre's formula