Verified answer

f(x) = 4x+2 and g(x) = 3x^(2) + 4x I assume 3x2 is meant to be 3x^(2)?

Hence f o g = 4[3x^(2) + 4x] + 2

= 12x^(2) + 16x + 2

f og (5) means the value of f of when x = 5. hence:

f o g(5) = 12*(5)^(2) + 16*5 + 2

= 12*25 + 80 + 2

= 382

Note how for f o g the g(x) is on the inside. You would get a total different result the other way round which would be g o f

H

f ( g(x) ) = f ( 3 x ² + 4x ) = 12 x ² + 16 x + 2

f ( g (5) ) = 300 + 80 + 2 = 382

First plug 5 into g(x)

3((5)^2)+ 4(5) = 95

Then plug "95" into f(x)

F(95)=4(95)+2= 382

382 is your answer. always read compostite functions from right to left. Plug 5 into g(x) then plug

g(5) into f(x). Another way of writing that would be F[g(5)]

f(x) = 4x + 2

g(x) = 3x^2 + 4x

g(5) = 3*(5^2) + 4*5

g(5) = 3*25 + 20

g(5) = 75 + 20

g(5) = 95

f(g(5)) = f(95)

f(g(5)) = 4*95 + 2

f(g(5)) = 380 + 2

f(g(5)) = 382

( f○g)(5) = 4g(5)+2 = 4(3*5^2+4*5) + 2

Can you finish it?