K(x)=x2 +1, g(y)=y2 -1, Find k(4) – g(4)?
I guess it is k(x) = x^2 + 1
and g(y) = y^2 - 1
We use "^" for an exponent.
To find k(4) just replace x by 4 in the equation.
k(4) = 4^2 + 1
k(4) = 16 + 1
k(4) = 17
Do the same for g(4) :
g(4) = 4^2 - 1
g(4) = 16 - 1
g(4) = 15
k(4) - g(4) = 17 - 15 = 2
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
K(x)=x2 +1, g(y)=y2 -1, Find k(4) – g(4)?
I guess it is k(x) = x^2 + 1
and g(y) = y^2 - 1
We use "^" for an exponent.
To find k(4) just replace x by 4 in the equation.
k(4) = 4^2 + 1
k(4) = 16 + 1
k(4) = 17
Do the same for g(4) :
g(4) = 4^2 - 1
g(4) = 16 - 1
g(4) = 15
k(4) - g(4) = 17 - 15 = 2