Joe wishes to hang a sign weighing 735 N so that cable A, attached to the store, makes a 30.0° angle, as?
Joe wishes to hang a sign weighing 735 N so that cable A, attached to the store, makes a 30.0° angle, as shown below. Cable B is horizontal and attached to an adjoining building. What is the tension in cable B?http://www.webassign.net/gphys/7-16.gif
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Let:
S be the tension in the left hand cable,
T be the tension in the right hand cable.
Resolving vertically:
S cos(30) = 735 ...(1)
Resolving horizontally:
S sin(30) = T ...(2)
Dividing (2) by (1):
tan(30) = T / 735
T = 424 N. to 3 sig. fig.
That Cable
was too easy for me 10 years age, :) it's just too rough for this time of night :) gravity, 30 degree,90 degree, calculations, divided ,oooffff, not in a mood :)