Resolva, em ℝ, as seguintes inequações:
a) |x² – 3x – 4| ≤ 6
b) |x² – x – 4| > 2
se possivel com ecplicações
Ola łαvi
a1) |x² – 3x – 4| ≤ 6
x² - 3x - 10 ≤ 0
delta
d² = 9 + 40 = 49
d = 7
x1 = (3 + 7)/2 = 5
x2 = (3 - 7)/2 = -2
-2 ≤ x ≤ 5
a2) |x² – 3x – 4| ≤ -6
x² - 3x + 2 ≤ 0
d² = 9 - 8 = 1
d = 1
x1 = (3 + 1)/2 = 2
x2 = (3 - 1)/2 = 1
1 ≤ x ≤ 2
b1) |x² – x – 4| > 2
x² - x - 6 > 0
d² = 1 + 24 = 25
d = 5
x1 = (1 + 5)/2 = 3
x2 = (1 - 5)/2 = -2
x > 3
x < -2
b2) |x² – x – 4| > -2
x² - x - 2 > 0
d² = 1 + 8 = 9
d = 3
x1 = (1 + 3)/2 = 2
x2 = (1 - 3)/2 = -1
x > 2
x < -1
pronto
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Answers & Comments
Ola łαvi
a1) |x² – 3x – 4| ≤ 6
x² - 3x - 10 ≤ 0
delta
d² = 9 + 40 = 49
d = 7
x1 = (3 + 7)/2 = 5
x2 = (3 - 7)/2 = -2
-2 ≤ x ≤ 5
a2) |x² – 3x – 4| ≤ -6
x² - 3x + 2 ≤ 0
delta
d² = 9 - 8 = 1
d = 1
x1 = (3 + 1)/2 = 2
x2 = (3 - 1)/2 = 1
1 ≤ x ≤ 2
b1) |x² – x – 4| > 2
x² - x - 6 > 0
delta
d² = 1 + 24 = 25
d = 5
x1 = (1 + 5)/2 = 3
x2 = (1 - 5)/2 = -2
x > 3
x < -2
b2) |x² – x – 4| > -2
x² - x - 2 > 0
delta
d² = 1 + 8 = 9
d = 3
x1 = (1 + 3)/2 = 2
x2 = (1 - 3)/2 = -1
x > 2
x < -1
pronto