please help out...really confused!!
and what if it wasn't not squared?? how would we solve it??
3 x (-1/√3)²
--> 3 x (1/3) [(-1/√3)² means (-1/√3) x (-1/√3), that is, negative multiplied to negative, which gives answer as positive.]
--> 1
Depends if you want it to. Ultimately, it doesn't matter, however.
Say I have this:
-1 / sqrt(3)
I can also write it like this:
1 / -sqrt(3)
These are equivalent things as long as I don't use the negative sign twice.
But to show why it doesn't matter in this particular example, let me write it like this:
(-1) * (1/sqrt(3))
Then you square that:
[(-1) * (1/sqrt(3))]^2
(-1)^2 * (1/sqrt(3))^2
1 * 1/3
1/3
See? The negative sign went away. Squaring a negative number will always result in a positive number.
If you then multiply that by 3, you get 1.
The sign is not applied to either 1 or â3, but rather the whole thing. It can go either to the 1 or the â3, you will still get the same answer.
Yes
It won't
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Verified answer
3 x (-1/√3)²
--> 3 x (1/3) [(-1/√3)² means (-1/√3) x (-1/√3), that is, negative multiplied to negative, which gives answer as positive.]
--> 1
Depends if you want it to. Ultimately, it doesn't matter, however.
Say I have this:
-1 / sqrt(3)
I can also write it like this:
1 / -sqrt(3)
These are equivalent things as long as I don't use the negative sign twice.
But to show why it doesn't matter in this particular example, let me write it like this:
(-1) * (1/sqrt(3))
Then you square that:
[(-1) * (1/sqrt(3))]^2
(-1)^2 * (1/sqrt(3))^2
1 * 1/3
1/3
See? The negative sign went away. Squaring a negative number will always result in a positive number.
If you then multiply that by 3, you get 1.
The sign is not applied to either 1 or â3, but rather the whole thing. It can go either to the 1 or the â3, you will still get the same answer.
Yes
It won't