In the circuit below, a constant current of i = 1.93 A flows from b to c through the 6 Ω resistor?
http://s1250.photobucket.com/albums/hh532/jch75/
Calculate the potential difference between points a and d
More Questions From This User See All
Answers & Comments
Verified answer
Vbc = 1.93 x 6 = 11.58 volts
that voltage is also across the 3 Ω resistor and the current in that leg is 11.58/3 = 3.86 amps
those two add up to flow through the 23 Ω resistor, total = 1.93 x 3 = 5.79 amps
and the voltage across that resistor is 5.79 x 23 = 133.17 volts
therefore Vad = 133.17 + 11.58 = 144.75 volts
V across 6 ohm E = (IR), = 1.93 x 6, = 11.58V.
Current through 3 ohm I = (E/R), = 11.58/3, = 3.86A.
Circuit current = (3.86 + 1.93) = 5.79A.
V across 23 ohm E = (IR), = 5.79 x 23, = 133.17V.
PD between A and D = (133.17 + 11.58) = 144.75V.
The current through the 3 ohm resistor is 3.86 amps. The total current throught the 23 ohm resistor is 1.93+3.86=5.79 amps, so the voltage is 5.79*23=133.17 volts.