Find:
∫e^(x/3)dx =_______+C
u=x/3
Question Closed
As you say, do a u-sub with u=x/3. Then du is (1/3)dx or 3du=dx. Then the integral just becomes:
3 Int e^u du, which is just 3e^(x/3) + C.
EDIT: Thanks....does that mean I get the 10 points? :)
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Verified answer
As you say, do a u-sub with u=x/3. Then du is (1/3)dx or 3du=dx. Then the integral just becomes:
3 Int e^u du, which is just 3e^(x/3) + C.
EDIT: Thanks....does that mean I get the 10 points? :)