I know what the answer is already, I just want someone to explain the steps for me.
if you are given the area (11 + √112) units^2, then the side is:
s^2 = area
s = √(11 + 4√7)
perimeter = 4s = 4√(11 + 4√7) units
the radical of the radical can be simplified to:
√(11 + 4√7) = 2 + √7
so...the perimeter is: 8 + 4√7 units
MAD
If the area of a square is 11 +√112,
calculate its perimeter.
If area = s^2, perimeter = 4s
s^2 = 11 + 4√7
s = 4.6458
4s = 18.5832
The perimeter of the square is 18.5832.
A = 11+√112 = s²
so s = √(11+√112)
perimeter = 4s
perimeter = 4√(11+√112)
this can be simplified a bit
√112 = √(7•4•4) = 4√7
perimeter = 4√(11+4√7)
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Verified answer
if you are given the area (11 + √112) units^2, then the side is:
s^2 = area
s = √(11 + 4√7)
perimeter = 4s = 4√(11 + 4√7) units
the radical of the radical can be simplified to:
√(11 + 4√7) = 2 + √7
so...the perimeter is: 8 + 4√7 units
MAD
If the area of a square is 11 +√112,
calculate its perimeter.
If area = s^2, perimeter = 4s
s^2 = 11 + 4√7
s = 4.6458
4s = 18.5832
The perimeter of the square is 18.5832.
A = 11+√112 = s²
so s = √(11+√112)
perimeter = 4s
perimeter = 4√(11+√112)
this can be simplified a bit
√112 = √(7•4•4) = 4√7
perimeter = 4√(11+4√7)