If R1 = 2.00 Ω, R2 = 5.00 Ω and R3 = 6.00 Ω, what is the current through the 6.00 Ω resistor? (Show how you?
If R1 = 2.00 Ω, R2 = 5.00 Ω and R3 = 6.00 Ω,
what is the current through the 6.00 Ω resistor?
(Show how you arrived at your result and include units)
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I love you man.
And I love even more how you failed to show us the diagram.
commence with V = I R, so I = V/R capacity = I V, substituting for I (from I = V/R ) we get capacity = V squared / R V = 9, V squared = 80 one finished capacity = capacity R1 + capacity R2 + capacity R3. = 80 one / 9 + 80 one / 3 + 80 one / a million = 9 + 27 + 80 one = 117
at least tell what r the connection?