Homework help with electrostatics in physics
Given, charge of one electron (e) = 1.6 x 10⁻¹⁹c
Number of electrons (n) = 1.5 x 10⁷
Charge (Q) = ?
We know that:-
Charge (Q) = ne = 1.5 x 10⁷ x 1.6 x 10⁻¹⁹
= 2.4 x 10⁻¹²c.
Charge of one electron is -1.602 x 10^(-19) coulombs, so the charge of 1.5 x 10^7 electrons is -2.403 x 10^(-12) coulombs; the charge on an object that LOSES that many electrons will be
+2.403 x 10^(-12) coulombs.
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Answers & Comments
Given, charge of one electron (e) = 1.6 x 10⁻¹⁹c
Number of electrons (n) = 1.5 x 10⁷
Charge (Q) = ?
We know that:-
Charge (Q) = ne = 1.5 x 10⁷ x 1.6 x 10⁻¹⁹
= 2.4 x 10⁻¹²c.
Charge of one electron is -1.602 x 10^(-19) coulombs, so the charge of 1.5 x 10^7 electrons is -2.403 x 10^(-12) coulombs; the charge on an object that LOSES that many electrons will be
+2.403 x 10^(-12) coulombs.