If 2.5 moles of zinc sulfide are heated with 4.0 moles of oxygen, which reactant is in excess, and by how much?
2 ZnS + 3 O2 + heat → 2 ZnO + 2 SO2
If 2.5 moles of zinc sulfide are heated with
4.0 moles of oxygen, which reactant is in excess, and by how much?
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If you have 2.5 mol of ZnS then according to the equation you would need 3/2 more mol of O2. So is 2.5 x 3/2 = to 4? Well, it is equal to 3.75, so therefore you have more than enough O2 to use up all the ZnS. Once the 2.5 mol of ZnS is gone the reaction stops.
There should be 4.00 - 3.75 or 0.25 mol of O2 left.