Verified answer

mass of AlCl3 = (mass of Cl2) ÷ (Molar mass of Cl2) x (2 moles of AlCl3 / 3 moles of Cl2) x (Molar mass of AlCl3)

mass of AlCl3 = (11.5 g) ÷ (70.906 g/mol) x (2/3) x (133.34 g/mol)

mass of AlCl3 = 14.4 g

This is the third problem that you solve in exactly the same way.

Mass Cl2 --> moles Cl2 --> Moles AlCl3 --> mass AlCl3