6x²-5xt-6t²......a bit trickier. Since last sign is negative then one factor is positive and one negative. The 2 end integers are each 6, product of 2 and 3. We need one product (the negative one) 5 larger than the positive product, like this:
(3x + 2)(2x - 3)....answer (expand this one and you'll see it works)
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x²+9xy+18y²......6*3=18 & 6+3=9, so...
(x+6)(x+3).....answer
6x²-5xt-6t²......a bit trickier. Since last sign is negative then one factor is positive and one negative. The 2 end integers are each 6, product of 2 and 3. We need one product (the negative one) 5 larger than the positive product, like this:
(3x + 2)(2x - 3)....answer (expand this one and you'll see it works)