(5/ x + 1) − (1/ 2) = (1 /6x + 6)
(5/ x + 1) − (1/ 2) = (1 /6(x + 1))
(5/ x + 1) - (1 /6(x + 1)) = 1/2
(30-1) / 6(x+1) = 1/2
(29/6) * 2 = x+1
29/3 - 1 = x
26/3 = x
x = 26/3
I was a little confused by the punctuation so I'll rewrite this. Let me know if i misinterpreted.
5/(x+1) - 1/2 = 1/(6x+6)
Rewrite the right side to be 1/(6*(x+1)) which gives you a common denominator. Now get everything on one side...
5/(x+1) - 1/2 - 1/(6*(x+1)) = 0
multiply both sides by 6 to simplify the bottom
30/(x+1) - 6/2 - 1/(x+1) = 0
simplify to get
29/(x+1) - 3 = 0
now just solve for x
29/(x+1) = 3
29 = 3(x+1)
29/3 = x+1
29/3 - 3/3 = x
Final answer is x = 26/3
The question is not clear so, I will answer in different aspect:
1. if 1/6x is separate and +6 is separate in Right hand side and 5/x is separate and +1 is seperate in Left hand side
(5/x)+1-(1/2) = (1/6x) +6
or, (5/x)-(1/6x) = 6-1+(1/2)
or, (6*5 - 1)/6x = 5 + (1/2)
or, 29/6x = (10 +1)/2
or (29 * 2)/11 = 6x;
or, 58/(11*6) = x
or, x = 58/66
2. if 1 is separate and 6x+6 is separate then the procedure is like the answer before mine.
or, x = 29/11
5/(x+ 1) - 1/2 = 1/(6x + 6)
29 = 3(x + 1)
26 = 3x => x = 26/3
29/ 6(x+1) = 1/2
29*2 = 6(x+1) [ cross multiplying]
58 = 6(x+1)
58/6 = x+1
9.67 = x+1
x = 9.67 -1
x = 8.67
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Verified answer
(5/ x + 1) − (1/ 2) = (1 /6x + 6)
(5/ x + 1) − (1/ 2) = (1 /6(x + 1))
(5/ x + 1) - (1 /6(x + 1)) = 1/2
(30-1) / 6(x+1) = 1/2
(29/6) * 2 = x+1
29/3 - 1 = x
26/3 = x
x = 26/3
I was a little confused by the punctuation so I'll rewrite this. Let me know if i misinterpreted.
5/(x+1) - 1/2 = 1/(6x+6)
Rewrite the right side to be 1/(6*(x+1)) which gives you a common denominator. Now get everything on one side...
5/(x+1) - 1/2 - 1/(6*(x+1)) = 0
multiply both sides by 6 to simplify the bottom
30/(x+1) - 6/2 - 1/(x+1) = 0
simplify to get
29/(x+1) - 3 = 0
now just solve for x
29/(x+1) = 3
29 = 3(x+1)
29/3 = x+1
29/3 - 1 = x
29/3 - 3/3 = x
26/3 = x
Final answer is x = 26/3
The question is not clear so, I will answer in different aspect:
1. if 1/6x is separate and +6 is separate in Right hand side and 5/x is separate and +1 is seperate in Left hand side
(5/x)+1-(1/2) = (1/6x) +6
or, (5/x)-(1/6x) = 6-1+(1/2)
or, (6*5 - 1)/6x = 5 + (1/2)
or, 29/6x = (10 +1)/2
or (29 * 2)/11 = 6x;
or, 58/(11*6) = x
or, x = 58/66
2. if 1 is separate and 6x+6 is separate then the procedure is like the answer before mine.
or, x = 29/11
5/(x+ 1) - 1/2 = 1/(6x + 6)
29 = 3(x + 1)
26 = 3x => x = 26/3
(5/ x + 1) − (1/ 2) = (1 /6x + 6)
(5/ x + 1) − (1/ 2) = (1 /6(x + 1))
(5/ x + 1) - (1 /6(x + 1)) = 1/2
(30-1) / 6(x+1) = 1/2
29/ 6(x+1) = 1/2
29*2 = 6(x+1) [ cross multiplying]
58 = 6(x+1)
58/6 = x+1
9.67 = x+1
x = 9.67 -1
x = 8.67