I'm confused about using pi.
The angles you are given are given in radians... if you want to convert to degrees do this
degrees = x radians * 180 degrees / pi radians
so
In the case of theta = π/3
theta = π/3 * 180/π
= 180/3
= 60 degrees
You can do the same for pi/6 and you should get 30 degrees.
Sine Addition Formula
sin(a+b) = sin(a)cos(b) + sin(b)cos(a)
Cosine Addition Formula
cos(a+b) = cos(a)cos(b) - sin(a)sin(b)
So
sin(x+(π/3)) = sin(x)cos(π/3) + sin(π/3)cos(x)
cos(x+(π /6))= cos(x)cos(π /6) - sin(x)sin(π /6)
Simplifying
sin(x+(π/3)) = sin(x)cos(60) + sin(60)cos(x)
= 1/2 * sin(x) + sqrt(3)/2 cos(x)
cos(x+(π /6))= cos(x)cos(30) - sin(x)sin(30)
= sqrt(3)/2 cos(x) - 1/2sin(x)
sin(x+(π/3))-cos(x+(π /6))= 1/2 * sin(x) + sqrt(3)/2 cos(x) - [sqrt(3)/2 cos(x) - 1/2sin(x)]
= 1/2 * sin(x) + sqrt(3)/2 cos(x) - sqrt(3)/2 cos(x) + 1/2sin(x)
= 1/2 sin(x) + 1/2 sin(x)
= sin(x)
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Verified answer
The angles you are given are given in radians... if you want to convert to degrees do this
degrees = x radians * 180 degrees / pi radians
so
In the case of theta = π/3
theta = π/3 * 180/π
= 180/3
= 60 degrees
You can do the same for pi/6 and you should get 30 degrees.
Sine Addition Formula
sin(a+b) = sin(a)cos(b) + sin(b)cos(a)
Cosine Addition Formula
cos(a+b) = cos(a)cos(b) - sin(a)sin(b)
So
sin(x+(π/3)) = sin(x)cos(π/3) + sin(π/3)cos(x)
cos(x+(π /6))= cos(x)cos(π /6) - sin(x)sin(π /6)
Simplifying
sin(x+(π/3)) = sin(x)cos(60) + sin(60)cos(x)
= 1/2 * sin(x) + sqrt(3)/2 cos(x)
cos(x+(π /6))= cos(x)cos(30) - sin(x)sin(30)
= sqrt(3)/2 cos(x) - 1/2sin(x)
so
sin(x+(π/3))-cos(x+(π /6))= 1/2 * sin(x) + sqrt(3)/2 cos(x) - [sqrt(3)/2 cos(x) - 1/2sin(x)]
= 1/2 * sin(x) + sqrt(3)/2 cos(x) - sqrt(3)/2 cos(x) + 1/2sin(x)
= 1/2 sin(x) + 1/2 sin(x)
= sin(x)