Verified answer

Bring the 2x^2 over and minus it from the 17x^2. This should give you: 15x^2 -11x +2 =0. From here you use the quadratic equation. Make a=15, b=-11, and c=2. I would do it myself but I'm typing this on a phone and would take me a year to write out :P

17x^2-11x+2 = 2x^2

Subtract 2x^2 from both sides:

17x^2-11x+2-2x^2 = 2x^2-2x^2

15x^2-11x+2 = 0

Factor the trinomial:

(5x-2)(3x-1) = 0

Set each factor equal to 0 and solve for x:

5x-2 = 0

5x-2+2 = 0+2

5x = 2

5x/5 = 2/5

x = 2/5

3x-1 = 0

3x-1+1 = 0+1

3x = 1

3x/3 = 1/3

x = 1/3

Answer: x=2/5 or x=1/3

subtract 2x^2 from the left and right, resulting in 15x^2 - 11x + 2

then factor.

-5 and -6 are your two numbers.

(5x-2)(3x-1)

then you set each equal to zero to find the other.

5x-2: x=2/5

3x-1: x=1/3

Hope this helps!

-Jerian

Move all your terms to the left hand side thus combining like terms. This will leave you with a quadratic equal to zero. So now just factor it and set each factor equal to zero and solve!

....You should probably study more if you don't understand this. Ask for review from your teacher because if you rely on yahoo answers for this kind of math, it will bite you in the *** when you move on to algebra 2.

I could be wrong, but O don't know if you can...

is this where ceasar really lived...?