[dy/dx] = (-2/x²) -3 is the slope m of the line y = mx +c at the point where x = 1
m = -2 - 3 = - 5. The equation is y = -5x + c.
Now plug x = 1 into the function of the curve to which m is the slope of the tangent line. This will give you the value of y at that point. Let's call it v. From v = -5x + c, you can get the value of c, giving you the complete tangent equation.
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[dy/dx] = (-2/x²) -3 is the slope m of the line y = mx +c at the point where x = 1
m = -2 - 3 = - 5. The equation is y = -5x + c.
Now plug x = 1 into the function of the curve to which m is the slope of the tangent line. This will give you the value of y at that point. Let's call it v. From v = -5x + c, you can get the value of c, giving you the complete tangent equation.
y or y = 2