m√3 = 12

m = 12/√3

m = 12 / √3 = 12 √3 / 3 = 4 √3

m√3 = 12

m = 4(√3)^2 / √3

m = 4(√3)

Original equation:

m√3 = 12

Divide both sides by √3:

m = 12/√3

At that point you are probably expected to rationalize the denominator so multiply top and bottom by √3:

m = (12√3)/3

m = 4√3

Answer:

m = 4√3

m√3=12

m = 12/√3 = (12√3)/(√3√3)=(12√3)/3=4√3

Does "m√3" mean m times the square root of 3?

In that case, divide both sides by sqrt(3).

m * sqrt(3) = 12

m = 12/sqrt(3).

Done.

Does it mean something else, like the m-th root of 3? That is 3^(1/m) = 12?

Then take the log of both sides.

(1/m) log 3 = log 12

Divide both sides by log 3

1/m = (log 12) / (log 3)

Take the reciprocal of both sides

m = (log 3) / (log 12)