How much C(s) (in kg) is needed to fill a blimp with H2? volume of blimp = 4.62 x 108 L (23 °C, 755 mmHg)?
Consider the use of C(s) as a reducing agent to synthesize hydrogen gas:
C(s) + H2O(g) ----------> CO(g) + H2(g)
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p = 755/760=0.993
T = 23 + 273 = 296 K
moles H2 = pV/RT = 0.993 x 4.62 x 10^8 / 0.08206 x 296 K=1.89 x 10^7
= moles C
mass C = 1.89 x 10^7 x 12.011 g/mol= 2.27 x 10^8 g = 2.27 x 10^5 Kg