How many molecules of N2 are in a 400.0 mL container at 780 mm Hg and 135°C?
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a. 7.38 × 10^21 molecules
b. 7.01 × 10^21 molecules
c. 2.12 × 10^22 molecules
d. 2.23 × 10^22 molecules
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Help again!
a. 7.38 × 10^21 molecules
b. 7.01 × 10^21 molecules
c. 2.12 × 10^22 molecules
d. 2.23 × 10^22 molecules
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Verified answer
780 mmHg = 1.013*10^5*780/760 Pa = 1.039*10^5 Pa
400 mL = 0.4*10^-3 m^3
T = 273+135 ° = 408°K
find n:
pV = nRT
n = pV/(RT)
n = 1.039*10^5*0.4*10^-3/(8.314*408)
n = 0.01225 moles
number of molecules = 0.01225*6.022*10^23 = 7.376*10^21 <--- ans.
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