How many liters of O2 gas, measured at 781mmHg and 25∘C, are required to completely react with 2.1mol of Al?
The ratio of Al to O2 in the balanced equation is 4:3. Please do not answer for me. Please just explain how to set up the problem, let me do the work so I can learn.
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4Al+3O2-->2Al2O3
First determine the limiting reactant. Once you determine the limiting reactant you will be able to calculate how many moles of O2 reacted. Then use the pV=nRT to solve for volume of O2 gas. Make sure you convert to match your R components.