How many g of a metal(ρ=9.98 g/cm3) are required to make a thin sheet with a thickness of 0.694 mm...?

May 2021 3 212 Report

How many g of a metal(ρ=9.98 g/cm3) are required to make a thin sheet with a thickness of 0.694 mm...?

and an area of 14.4 cm2? Report your answer to three decimal places.

I wasn't sure on how to go about this problem so if someone could solve it and explain it it would be appreciated. Thanks. :D

Well you're given everything...

p = 9.98 g/cm3 means for every cubic centimeter of metal you will have 9.98g of mass.

Step 1 - Find the cubic area you are covering(make sure everything is in centimeters!):

It is just 0.0694 cm (thickness) multiplied by the area 14.4 cm^2

Which gives you a volume of 0.999 cm^3 or approximately 1 cubic centimeter

Multiply it by 9.98g/cm^3 and you get 9.97g

Thus you need 9.97 grams of metal.

Your density tells you how many grams per unit volume.

You are given in the problem a thickness and an area. Volume is simply area x thickness.

So, the volume is 9.99 cm^3.

Thus, the mass is 9.99 x 9.98 = 99.7 g.

Kirsten, we know that Mass=VolumeXdensity.

To find volume, it is area multiplied by thickness ie, 0.694*14.4 = 9.993

Now, mass= 9.993*9.98= 99.73014g

hopefully, this should be correct.