Factorise it by "completing the square" method.
Since 4 is a square number, get the negative and positive form, and stick an x in front, and leave it as a multiplied form.
It is equivalent to (x-2)(x+2)
You cannot fully solve it because this is an expression... if this is equal to zero however (usually a question assumes this), x becomes 2 and - 2.
This problem is a difference of two squares. the simplest way is to set the equation equal to zero: x² - 4 = 0
If you add 4 to both sides, you get: x² = 4
At that point, you take the square root of both sides: x = 2 or x = -2 (since either number squared would equal 4).
Technically, x² - 4 is an expression, not an equation, because there is no equality sign. So it can't be solved, just factored to (x + 2)(x - 2).
I assume you mean x^2 - 4 = 0?
First, you factor x^2 - 4 to get (x - 2)(x + 2) = 0
Then, set each part to zero,
x - 2 = 0 or x + 2 = 0
x = 2 or x = -2
Hope this helps you!
the problem would look like this x to the second - 4 = 0.
plus 4 to both side. and it would leave x to the second power = 4
now u take the sq root to both x to the second and 4 that would leave u x=2
factor... (x+2)(x-2)...if it is equal to zero then x=2 or -2... if not then leave it in factored form
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Factorise it by "completing the square" method.
Since 4 is a square number, get the negative and positive form, and stick an x in front, and leave it as a multiplied form.
It is equivalent to (x-2)(x+2)
You cannot fully solve it because this is an expression... if this is equal to zero however (usually a question assumes this), x becomes 2 and - 2.
This problem is a difference of two squares. the simplest way is to set the equation equal to zero: x² - 4 = 0
If you add 4 to both sides, you get: x² = 4
At that point, you take the square root of both sides: x = 2 or x = -2 (since either number squared would equal 4).
Technically, x² - 4 is an expression, not an equation, because there is no equality sign. So it can't be solved, just factored to (x + 2)(x - 2).
I assume you mean x^2 - 4 = 0?
First, you factor x^2 - 4 to get (x - 2)(x + 2) = 0
Then, set each part to zero,
x - 2 = 0 or x + 2 = 0
x = 2 or x = -2
Hope this helps you!
the problem would look like this x to the second - 4 = 0.
plus 4 to both side. and it would leave x to the second power = 4
now u take the sq root to both x to the second and 4 that would leave u x=2
factor... (x+2)(x-2)...if it is equal to zero then x=2 or -2... if not then leave it in factored form