Verified answer

Let x=ay+d/cy−d and separate y

x(cy -d)=ay+d

cxy-dx=ay+d

cxy-ay=d+dx

y(cx-a)=d+dx

y=dx+d/cx-a is the inverse function f^-1(x)

domain of f(x) =(-inf,d/c)U(d/c,inf)=range f^-1(x)

domain of f^-1(x)=(-inf,a/c)U(a/c,inf)=range of f(x)

ambiguous y = ax+d/cx-d ought to be any of here y = (ax+d) / (cx-d) y = ax + (d/cx) – d y = (ax+d/cx) – d or a number of others. discover ways to apply parans. yet see the example under. No! you do no longer "turn it over" to locate the inverse. you're completely incorrect. You replace x and y and remedy for y. as an occasion y = 2x + a million x = 2y + a million 2y = x – a million y = (x – a million) / 2 or y = (x/2) – (a million/2) .

Switch the 'Y' with the 'X'

y = ax + d/cx - d

to

x = ay + d/cy - d

then solve it