Hi,
x + 13√x + 12 = (√x + 12)(√x + 1) <==ANSWER
I hope that helps!! :-)
(âx +12)(âx +1)
Let u=âx
Then, u² = x
so,
x+13âx+12 =
u² + 13u + 12 =
(u+1)(u+12) =
(âx + 1)(âx + 12)
(âx)² + 13âx + 12
assume that âx = a
a² + 13a + 12
= (a + 12)(a + 1)
= (âx + 12)(âx + 1)
(sqrt(x)+(12)*((sqrt(x) + 1)
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Verified answer
Hi,
x + 13√x + 12 = (√x + 12)(√x + 1) <==ANSWER
I hope that helps!! :-)
(âx +12)(âx +1)
Let u=âx
Then, u² = x
so,
x+13âx+12 =
u² + 13u + 12 =
(u+1)(u+12) =
(âx + 1)(âx + 12)
(âx)² + 13âx + 12
assume that âx = a
a² + 13a + 12
= (a + 12)(a + 1)
= (âx + 12)(âx + 1)
(sqrt(x)+(12)*((sqrt(x) + 1)