trig identity is right. You may not be able to convert the function of ø to a function of x, but you can certainly convert it into a parametric function of t.
Taking t = ø, say the following:
x = r*cos(t/3)
y = r*sin(t/3)
substituting r with its function, you have:
x = sin^3(t/3)*cos(t)
y = sin^3(t/3)*sin(t)
That graph (taking the x and y coordinates to be separate functions of t) will give you the exact same picture.
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trig identity is right. You may not be able to convert the function of ø to a function of x, but you can certainly convert it into a parametric function of t.
Taking t = ø, say the following:
x = r*cos(t/3)
y = r*sin(t/3)
substituting r with its function, you have:
x = sin^3(t/3)*cos(t)
y = sin^3(t/3)*sin(t)
That graph (taking the x and y coordinates to be separate functions of t) will give you the exact same picture.